00:01
Hello students, we are going to write here simply support a team beam of length.
00:06
So length is given subjected to uniform load.
00:08
W modeled as log normal random variable with the following mean and coefficient of variation.
00:14
M .w is given.
00:15
S .w is given.
00:16
We are going to find a and b part.
00:18
So let's start with our answering part.
00:21
In the first case, mu k value is given as 20 newton.
00:27
Clone newton per minute.
00:28
So let's erase this again.
00:30
Clone newton per minute so we are going to write here for this this is s w s point to as w s point two we are going to write here for this so this must be coefficient of coefficient of variation variation we are going to write here for this this must be written as is given by cov is equivalent to sigma divided by mu so we are going to write here for this this must be point two value is equivalent to sigma divided by 20 so basically if i write here for this sigma is 20 multiplied by point 20 multiplied by point two so we are going to write here for clone newton so this must be in the very first case so this must be our standard aviation standard standard aviation so basically if i write here for this in the first case if the maximum moment that the beam can register equal to mr is equal to 1400 clonuton what is the probability of failure of boom of beam so if i write here for this this must be this must be written as this is mr mr value is 140 kilo newton per minute.
02:17
So if i write here for this, this must be maximum binding moment.
02:26
Binding moment we are writing here.
02:30
This must be written as is simply supported.
02:36
It simply supported.
02:40
If i write here for this, is given by mr.
02:46
This must be mr value is wl squared divided by this must be divided by 8.
02:58
And here w is uniformly, w is uniformly distributed.
03:15
Uniformly distributed.
03:16
So basically if i write here for this, this must be 140 is equivalent to so, w value is, this must be multiplied by l square...