intfracpi4^fracpi2 (sin^2x - cos^2x)dx = ?

Name: intfracpi4^fracpi2 (sin^2x - cos^2x)dx = ?
Uploaded: 2022-06-28T19:31:34-08:00
Duration: 2 min 19 s
Channel: Gaurav Kalra
Description: intfracpi4^fracpi2 (sin^2x - cos^2x)dx = ?

Question

Gaurav Kalra · Accepted Answer

Step 1: Use the property that cos^2(x) - sin^2(x) = cos(2x) to rewrite the integral as ∫(cos(2x)

Question

$int_{frac{pi}{4}}^{frac{pi}{2}} (sin^2x - cos^2x)dx = ? $

Please give Ace some feedback