Single Answer Choice Type: 17. If the system is in...

Single Answer Choice Type: 17. If the system is in equilibrium \( \left(\cos 53^{\circ}=3 / 5\right) \), then the value of ' \( P \) ' is 1) 16 N 2) 4 N 18. Two balls are moving on a table. One has the 4) \( \sqrt{232} N \) \( V_{x}=1 \mathrm{~ms}^{-1}, V_{y}=\sqrt{3} \mathrm{~ms}^{-1} \) and 3) 10 N

The centre of mass, or centre of momentum, (CMS) frame is that in which the sum of the momenta (i.e., the total momentum) of all particles is zero. An electron has a kinetic energy K of 1 MeV and is incident on a proton at rest in the laboratory. The goal of this exercise is to calculate the speed of the CMS frame moving relative to the laboratory. (a) Express the initial energies Ee, Ep and initial momenta pe, pp of the electron and proton respectively (with c, me, mp, K). (b) What are the total energy Etot and the total momentum ptot before collision? (c) Express the transformed momentum p 0 tot in the CMS frame and obtain the speed v of the CMS frame with respect to the laboratory frame. The rest mass of the electron is 0.511 MeV/c2 . The rest mass of a proton is 938 MeV/c2

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