00:01
In this problem, we have been given that there is a singly charged ion, and this singly charged ion is moving in a region of magnetic field, such that the magnetic field strength, that is 1 .2 tesla, and this charged particle is moving in a circular path of radius 12 .5 centimeter, which is 0 .125 in terms of meters.
00:28
And it's given that the speed of this ion, let's represent that using we, that is given as 9 times 10 raise to 4 meter per second, and we are required to determine the mass of this ion.
00:45
So first we observe that the charge that's given, that is due to a singly charged ion, which will be 1 .6 into 10 raise 2 minus 19 column.
00:57
The reason being that if we have an atom, that atom will become singly charged when there is a loss or gain of proton.
01:08
And the proton carries a charge of minus 1 .6 times 10 raised to minus 19 column.
01:14
But here we will take its magnitude because here we will be equating the magnetic force which provides the necessary centripetal force.
01:23
So we'll equate both of them.
01:24
So this is the expression which will give the magnetic force.
01:27
And this expression will give the centipedal force...