Question

72) \frac{\sin \theta + \csc \theta}{\sin \theta - \csc \theta} = -2\tan^2 \theta \newline A) Identity \newline B) Not an Identity

          72) \frac{\sin \theta + \csc \theta}{\sin \theta - \csc \theta} = -2\tan^2 \theta \newline A) Identity \newline B) Not an Identity
        
72) (sinθ+ cscθ)/(sinθ- cscθ) = -2tan^2 θA) Identity B) Not an Identity

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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(sin heta +csc heta )/(sin heta -csc heta )=-2tan^(2) heta A) Identity B) Not an Identity sin+csc 72) =-2tan20 sin -csc A) Identity B Not an Identity
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Transcript

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00:01 This question asks us to basically simplify this expression down to either sine theta, cosine theta, tangent theta, or co -secent theta.
00:10 So what i'm going to do is i'm going to start by writing secant theta as 1 over cosine theta, co -saceteta as 1 over sine theta, and then on the bottom, 1, and then plus sine theta over cosine theta.
00:25 Okay? so what that means is i'm going to then take and multiply all of this by the common denominator, which is sine theta, cosine, theta.
00:37 So i'm going to do that on the top and the bottom, all right? so essentially i'm multiplying by one.
00:43 So that result is sine theta, okay, because the cosine theta cancels, plus cosine theta because the sine theta cancels, divided by one becomes sine theta...
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