What is repulsive electrical force between two protons 11.89×10^-15m apart from each other in an atomic nucleus? k= 8.988×10^9 N.m^2/C^2. Charge of proton= 1.601×10^-19 C.
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Step 1: Calculate the force using Coulomb's law formula: \( F = \frac{k \cdot q^2}{r^2} \) Show more…
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