00:01
Hello students, in this question we have given this data of blood groups and by using that in the a part in that first question we have to find the probability that a randomly selected person does not have the type b positive blood so that means we have to find the probability of b positive dash.
00:22
So now we know that probability of b positive dash that means probability of event a dash is nothing but 1 minus probability of b positive so therefore now this is equal to 1 minus probability of b positive is 8 % that is 0 .08 so therefore the required probability is 0 .92 that is the probability of a person does not have the type b positive blood is 0 .92.
00:56
Then in the second question we have to calculate the probability that the randomly selected person is o negative or ab.
01:06
Now ab that means ab positive and also ab negative so therefore the required probability required probability is equal to probability of o negative plus probability of ab positive plus probability of ab negative.
01:34
Now we have given probability of o negative is equal to 9 % ab positive is 2 % and ab negative is 1 % so this is equal to 0 .09 plus 0 .02 plus 0 .01 and that is equal to 0 .12.
01:55
Therefore the probability of o negative or ab is 0 .12.
01:59
Then in the third question we have to calculate the probability such that the blood person's blood is not a type o and nor it is positive so that means we have to consider the blood groups other than o so we have to consider a, ab and b and all are negative so therefore we can write the required probability required probability as probability of ab minus plus probability of a minus plus probability of b minus.
02:42
Now we have given this probability as 0 .02 plus 0 .01 plus 0 .07 and that is equal to 0 .1.
02:56
Therefore the probability of a person is not type o and nor he is positive is 0 .1...