Size of a Black Hole #2 What is the Schwarzschild Radius of a Black Hole that contains 2.28 x 10^34 kg?
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67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \) \( M \) = Mass of the black hole = \( 2.28 \times 10^{34} \, \text{kg} \) \( c \) = Speed of light = \( 3 \times 10^8 \, \text{m/s} \) Show more…
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