Question

1. Sketch and shade the region that corresponds to the solution set for the following system of inequalities and indicate whether the solution set is bounded or unbounded. Label all boundary lines and the exact coordinates of all corner points (if any) on your graph. 2x + 3y ? 12 2x + 3y > -6 3x + y > 4 0 ? x ? 4, y ? 0

          1. Sketch and shade the region that corresponds to the solution set for the following
system of inequalities and indicate whether the solution set is bounded or unbounded.
Label all boundary lines and the exact coordinates of all corner points (if any) on your
graph.

2x + 3y ? 12
2x + 3y > -6
3x + y > 4
0 ? x ? 4, y ? 0

1. Sketch and shade the region that corresponds to the solution set for the following
system of inequalities and indicate whether the solution set is bounded or unbounded.
Label all boundary lines and the exact coordinates of all corner points (if any) on your
graph.

2x + 3y ? 12
2x + 3y > -6
3x + y > 4
0 ? x ? 4, y ? 0

Added by Kristin H.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Donna Densmore

05/04/2023

Step 1

First, we need to rewrite the inequalities in the slope-intercept form (y = mx + b): 2x + 3y < 12 can be rewritten as y < -\frac{2}{3}x + 4 2r + 3"> -6 can be rewritten as y > -\frac{2}{3}x - 2 3r + y > 4 can be rewritten as y > -3x + 4 0 < +54, "20 seems to Show more…

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Sketch and shade the region that corresponds to the solution set for the following system of inequalities and indicate whether the solution set is bounded or unbounded. Label all boundary lines and the exact coordinates of all corner points (if any) on your graph: 2x + 3y ≤ 12 2x + 3y > -6 3x + y > 4 0 ≤ x ≤ 4, y ≥ 0