Question

Sketch $\theta = -\frac{11\pi}{4}$ in standard position.

          Sketch $\theta = -\frac{11\pi}{4}$ in standard position.
        
Sketch θ = -(11π)/(4) in standard position.

Added by Andrew K.

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Sketch heta =-(11pi )/(4) in standard position. 11 in standard position 4 Sketch 0= X Drag to show the angle
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Transcript

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00:01 Here, we're given an angle and we want to sketch it in standard position.
00:04 So we'll just say we have theta, which is equal to negative 14 pi over 3.
00:15 So in standard position, that basically means that one axis, one line of it is going to be here.
00:22 So i can immediately say, all right, half of it is right there.
00:25 That's one angle, is that way.
00:27 But that doesn't really help us.
00:28 What we really need to know is what angle is negative 14 over pi, 14 pi over 3.
00:34 So let's label some points knowing we're going to go negative...
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