00:01
Hey, hello everyone, so let's solve this doubt in this question.
00:05
Sample size is given as 80, whereas the mean value here x bar is equal to 13.
00:13
134 3 .04, whereas standard deviation is given 414 .04 .4 and degree of freedom.
00:23
The degree of freedom we are talking that is n minus 1 equals to 19.
00:27
So we can simply write it down here like for the 90 % of confidence.
00:34
If we are talking here, 90 % of confidence, we can simply write it down here t -sci divided by 2, that is sigma divided by root n.
00:50
So we can write it here 1 .729 and here 414 .04 .04, that is square root of 20, which we can write it here 1 .729, and here 414 .04, that is square root of 20, which which is equals to 160 .075.
01:05
Now in the same time we can calculate the 90 % confidence estimated.
01:13
So we can write it down here x bar at the mean minus e1...