Question

Sodium hydroxide reacts with sulfuric acid according to the following balanced chemical equation: 2 NaOH + H2SO4 -> 2 H2O + Na2SO4 How many mL of 0.400 M H2SO4 solution are required to completely neutralize 60.0 mL of 0.550 M NaOH solution? 82.5 mL 6.60 mL 72.7 mL 41.3 mL 13.2 mL 11.4 mL

          Sodium hydroxide reacts with sulfuric acid according to the following balanced chemical equation:

2 NaOH + H2SO4 -> 2 H2O + Na2SO4

How many mL of 0.400 M H2SO4 solution are required to completely neutralize 60.0 mL of 0.550 M NaOH solution?

82.5 mL
6.60 mL
72.7 mL
41.3 mL
13.2 mL
11.4 mL

Sodium hydroxide reacts with sulfuric acid according to the following balanced chemical equation:

2 NaOH + H2SO4 -> 2 H2O + Na2SO4

How many mL of 0.400 M H2SO4 solution are required to completely neutralize 60.0 mL of 0.550 M NaOH solution?

82.5 mL
6.60 mL
72.7 mL
41.3 mL
13.2 mL
11.4 mL

Added by Jennifer O.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ma Ednelyn Lim

03/28/2022

Step 1

0 mL of 0.550 M NaOH solution. Given: Volume of NaOH solution = 60.0 mL = 0.060 L Molarity of NaOH solution = 0.550 M Moles of NaOH = Molarity x Volume Moles of NaOH = 0.550 mol/L x 0.060 L Moles of NaOH = 0.033 mol Show more…

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Sodium hydroxide reacts with sulfuric acid according to the following balanced chemical equation: 2 NaOH + H2SO4 -> 2 H2O + Na2SO4 How many mL of 0.400 M H2SO4 solution are required to completely neutralize 60.0 mL of 0.550 M NaOH solution? 82.5 mL 6.60 mL 72.7 mL 41.3 mL 13.2 mL 11.4 mL