Question

Sodium ions enter the postsynaptic cell, resulting in a slight depolarization of that neuron. Calcium ions enter the cell, resulting in a slight depolarization of the postsynaptic neuron. The glutamate released from the axon terminal binds to both AMPA and NMDA receptors but only activates the NMDA receptors. The AMPA receptors depolarize the postsynaptic neuron and drive the Mg$^{2+}$ plug out of the NMDA channel.

          Sodium ions enter the postsynaptic cell, resulting in a slight depolarization of that neuron.
Calcium ions enter the cell, resulting in a slight depolarization of the postsynaptic neuron.
The glutamate released from the axon terminal binds to both AMPA and NMDA receptors but
only activates the NMDA receptors.
The AMPA receptors depolarize the postsynaptic neuron and drive the Mg$^{2+}$ plug out of the
NMDA channel.

Sodium ions enter the postsynaptic cell, resulting in a slight depolarization of that neuron.
Calcium ions enter the cell, resulting in a slight depolarization of the postsynaptic neuron.
The glutamate released from the axon terminal binds to both AMPA and NMDA receptors but
only activates the NMDA receptors.
The AMPA receptors depolarize the postsynaptic neuron and drive the Mg^2+ plug out of the
NMDA channel.

Added by Roberto J.

Psychology Openstax

Rosie M. Spielman 1st Edition

Instant Answer

Solved by Expert Lottie Adams

02/14/2021

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Step 1: Sodium ions enter the postsynaptic cell, causing a slight depolarization of the neuron. Show more…

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Sodium ions enter the postsynaptic cell, resulting in a slight depolarization of that neuron. Calcium ions enter the cell, resulting in a slight depolarization of the postsynaptic neuron. The glutamate released from the axon terminal binds to both AMPA and NMDA receptors but only activates the NMDA receptors. The AMPA receptors depolarize the postsynaptic neuron and drive the Mg^2+ plug out of the NMDA channel.