Question

Solve an equilibrium problem using an ICE table to calculate the pH of each of the following solutions: A. A solution that is 0.190 M in HC2H3O2 and 0.125 M in KC2H3O2. B. A solution that is 0.225 M in CH3NH2 and 0.110 M in CH3NH3Br. Express your answer to two decimal places.

Name: solve an equilibrium problem using an ice table to calculate the ph of each of the following solutionsa a solution that is 0190 m in hc2h3o2 and 0125 m in kc2h3o2 b a solution that is 0225 m 94464
Uploaded: 2022-04-11T15:30:53-08:00
Duration: 2 min 58 s
Channel: Shaiju T
Description: solve an equilibrium problem using an ice table to calculate the ph of each of the following solutionsa a solution that is 0190 m in hc2h3o2 and 0125 m in kc2h3o2 b a solution that is 0225 m 94464

          Solve an equilibrium problem using an ICE table to calculate the pH of each of the following solutions:
A. A solution that is 0.190 M in HC2H3O2 and 0.125 M in KC2H3O2.
B. A solution that is 0.225 M in CH3NH2 and 0.110 M in CH3NH3Br.
Express your answer to two decimal places.

Added by Juan Jos- B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Shaiju T

04/11/2022

Step 1

190 M HC2H3O2 and 0.125 M KC2H3O2): - Calculate pH using the formula pH = pKa + log([salt]/[acid]) - Given pKa for HC2H3O2 is 4.75 - pH = 4.75 + log(0.125/0.190) - pH = 4.75 + log(0.6579) - pH = 4.75 + (-0.182) - **\(\text{pH} = \mathbf{4.57}\)** Show more…

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Solve an equilibrium problem using an ICE table to calculate the pH of each of the following solutions: A. A solution that is 0.190 M in HC2H3O2 and 0.125 M in KC2H3O2. B. A solution that is 0.225 M in CH3NH2 and 0.110 M in CH3NH3Br. Express your answer to two decimal places.