Given that the engine hanging on the frame shown weighs 5 kN and the force in link CD is 12.5 kN tensile, use the right free body diagram (FBD) to find the internal forces at point E: Ne, Ve, Me.
a) Ne = 10 kN, Ve = 2.5 kN, Me = -2.5 kN-m (counterclockwise) causing T on top.
b) Ne = 10 kN, Ve = 2.5 kN, Me = +2.5 kN-m (clockwise) causing T on bottom.
c) Ne = 0, Ve = 2.5 kN, Me = +2.5 kN-m (clockwise) causing T on bottom.
d) Ne = 0, Ve = 2.5 kN, Me = -2.5 kN-m (counterclockwise) causing T on top.