We test the intervals $(-\infty, -2)$, $(-2, 2)$, and $(2, \infty)$.
For $x < -2$, let $x = -3$. Then $(-3 - 2)(-3 + 2) = (-5)(-1) = 5 > 0$.
For $-2 < x < 2$, let $x = 0$. Then $(0 - 2)(0 + 2) = (-2)(2) = -4 < 0$.
For $x > 2$, let $x = 3$. Then $(3 - 2)(3 + 2) =
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