Solve for $n$ $$_{n} P_{6}=12 \cdot_{n-1} P_{5}$$
Added by Albert M.
Step 1
Step 1: Rewrite the given equation using the formula for permutations: $n P_{6} = \frac{n!}{(n-6)!} = 12 \cdot \frac{(n-1)!}{(n-6-1)!} = 12 \cdot (n-1) P_{5}$. Show more…
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