00:01
All right, my dear student.
00:02
So let's find the total forces which are acting in the x -axis.
00:09
Let's call that submission of f -of -x.
00:13
So the first force, 100 newton's, making an angle 35 degrees with the horizontal, minus then 150 newton is towards negative axis, and 200 is towards negative axis with this angle 4 by 5.
00:32
So from here, the total forces in the x -axis equals minus 228 .08 newton's minus student.
00:40
Likewise, all the forces that are acting in the y -axis equals minus 100 times, this is towards negative y -axis.
00:54
Sign of the angle, there is 35 degrees.
01:00
This is again negative x -axis, this is 200 into the angle is 3 by 50.
01:06
So from here the total force is acting in the y -axis equals 177 .35 newtons.
01:16
So my student, we know that the resultant force is equal to the scale of the force of the horizontal component plus the square of the force of the vertical component.
01:33
So this equals, let's plug in the values.
01:37
This is minus 288 .91 newton squared plus this is 177 .35 newtons squared so the magnitude of the force equals my dear student 288 .91 square right my student newton so this is the magnitude of the force mario student now to find the angle theta we will use the formula that is sorry inverse of the tangent into the forces which are acting in the the ratio of the forces which are acting in the y -axis to the forces which are acting in the x -axis so this equals the arc of tangent function into the total forces in the y -axis equals 177 .35 divided by newtons divided by this is minus 228 .0 .08 newtons.
02:53
So from here the angle equals my student minus 37 .86 degrees.
03:02
All right.
03:03
Now the moment about o, all right...