Solve for v. (3)/(v-1)=-8-(7)/(v-2) Solve for v. $$\frac{3}{v-1} = -8 - \frac{7}{v-2}$$
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The common denominator for $-8$ and $\frac{7}{v-2}$ is $v-2$. Rewrite $-8$ as $\frac{-8(v-2)}{v-2}$. So the equation becomes: $$\frac{3}{v-1} = \frac{-8(v-2)}{v-2} - \frac{7}{v-2}$$ Show more…
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