Q3. \(i_c\) +\(V_c\)- 0.1 F \(V_c(0^-) = 10V\) \(V_D\) \(i_D\) diode Switch was open and at \(t=0s\), it is closed. -waveform at \(V_c\) and \(i_c\), \(V_D\), \(i_D\) -find value at \(V_c\) and \(i_c\) at following time 0 0.5 1 1+ 2 \(V_c\) \(i_c\)
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The switch is initially open, so there is no current flowing through the circuit. Therefore, Vc is 0V and ic is 0A at t=0. Show more…
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