Solve for $y$, where $y$ is a real number.\\ $\sqrt{-2y+8} + \sqrt{2y-4} = 2$\\ (If there is more than one solution, separate them with commas.)
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Subtract \sqrt(2y-4) from both sides of the equation: \sqrt(-2y+8) = 2 - \sqrt(2y-4) Show more…
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