00:01
For your problem here, you have a triangle abc.
00:03
We're told that side a is 10, the angle b is 26 degrees, and then side c is 12.
00:09
So the first thing you want to do is to figure out what case it is.
00:13
In here we see we have ourselves a side angle side.
00:16
What that means is we're going to have to use law of cosines, because law of cosines is the ones that we use for side angle side.
00:22
What that also means is we will not be doing a second case because the only times that happen is when you have a side -side angle case.
00:29
Now law sign says c squared is equal to a squared plus b squared minus 2ab cosine of c now in a case like this since we're trying to solve for side b over here what we're going to do is kind of rearrange this a little bit and use the other case.
00:49
So b squared is equal to a squared plus c squared minus 2 times a times c cosine of the angle b.
00:59
So when i replace this i would have b squared is equal to 12 squared plus 10 squared minus 2 times 12 times 10 and then cosine on the angle, which is 26.
01:13
Now make sure when you're calculating this, you do use radiant mode.
01:18
So when i evaluated this, i got an answer.
01:21
I'll go ahead and round to a couple decimal points of 28 .28 .94.
01:28
So then to solve for that side b, i'm going to take the same.
01:31
Square root.
01:33
So i got about 5 .3...