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Question 4 The SRK EOS can be defined as: $P = \frac{RT}{V-b} - \frac{\alpha a}{V(V+b)}$ Where: $a = \frac{0.42747(RT_c)^2}{P_c}$ $b = \frac{0.08664RT_c}{P_c}$ $m = 0.48508 + 1.55171\omega - 0.1561\omega^2$ $T_r = \frac{T}{T_c}$ $\alpha = [1 + m(1 - \sqrt{T_r})]^2$ Using the SRK EOS, calculate the pressure of 328.3 moles of a gas occupied in a 2.87 m³ container if the temperature is 90.9°C. Assume $T_c = 360.4$ K, $P_c = 86.42$ atm and $\omega = 1.086$. Enter your answer in Pascals.

          Question 4
The SRK EOS can be defined as:
$P = \frac{RT}{V-b} - \frac{\alpha a}{V(V+b)}$
Where:
$a = \frac{0.42747(RT_c)^2}{P_c}$
$b = \frac{0.08664RT_c}{P_c}$
$m = 0.48508 + 1.55171\omega - 0.1561\omega^2$
$T_r = \frac{T}{T_c}$
$\alpha = [1 + m(1 - \sqrt{T_r})]^2$
Using the SRK EOS, calculate the pressure of 328.3 moles of a gas occupied in a 2.87 m³
container if the temperature is 90.9°C. Assume $T_c = 360.4$ K, $P_c = 86.42$ atm and $\omega = 1.086$. Enter your answer in Pascals.

Question 4
The SRK EOS can be defined as:
P = (RT)/(V-b) - (α a)/(V(V+b))
Where:
a = (0.42747(RTc)^2)/(Pc)
b = (0.08664RTc)/(Pc)
m = 0.48508 + 1.55171ω - 0.1561ω^2
Tr = (T)/(Tc)
α = [1 + m(1 - √(Tr))]^2
Using the SRK EOS, calculate the pressure of 328.3 moles of a gas occupied in a 2.87 m³
container if the temperature is 90.9°C. Assume Tc = 360.4 K, Pc = 86.42 atm and ω = 1.086. Enter your answer in Pascals.

Added by Gloria J.

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