Solve \( \sin x+\cos x=\sqrt{2} \) if \( 0 \leqslant x \leqslant 2 \pi \)
Added by Lisa B.
Close
Step 1
The identity is \(\sin x + \cos x = \sqrt{2} \sin\left(x + \frac{\pi}{4}\right)\). Show more…
Show all steps
Your feedback will help us improve your experience
Matthew Elliott and 97 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use a calculator to solve the equation on the interval 0 ≤ x < 2π: sin(x) = -0.88
Donna D.
solve the equation 8sin x cos x = square root of 12, for 0 < x < pi/2
Khushbu R.
Solve each equation for exact solutions in the interval $0 \leq x<2 \pi$ $$2 \sin x \cos x=\sqrt{2} \cos x$$
Applications of Trigonometry and Trigonometric Identities
Trigonometric Equations
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD