Question

Solve sin(x)=-0.3 on 0<=x<2π There are two solutions, A and B, with A<B and A and B in radians to 4 decimal places. A= B= Solve sin(0.3) on 0<<2 There are two solutions, A and B, with A<B and A and B in radians to 4 decimal places.

Name: solve sinx 03 on 0x2 there are two solutions a and b with ab and a and b in radians to 4 decimal places a b solve sin03 on 02 there are two solutions a and b with ab and a and b in radians t 54164
Uploaded: 2023-09-01T01:46:49-08:00
Duration: 1 min 43 s
Channel: Gregory Higby
Description: solve sinx 03 on 0x2 there are two solutions a and b with ab and a and b in radians to 4 decimal places a b solve sin03 on 02 there are two solutions a and b with ab and a and b in radians t 54164

          Solve sin(x)=-0.3 on 0<=x<2π
There are two solutions, A and B, with A<B and A and B in radians to 4 decimal places.
A=
B=
Solve sin(0.3) on 0<<2
There are two solutions, A and B, with A<B and A and B in radians to 4 decimal places.

solve sinx 03 on 0x2 there are two solutions a and b with ab and a and b in radians to 4 decimal places a b solve sin03 on 02 there are two solutions a and b with ab and a and b in radians t 54164

Added by Daniel C.

Precalculus with Limits

Ron Larson 2nd Edition

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Solve sin(x)=-0.3 on 0<=x<2π There are two solutions, A and B, with A<B and A and B in radians to 4 decimal places. A= B= Solve sin(0.3) on 0<<2 There are two solutions, A and B, with A<B and A and B in radians to 4 decimal places.