Solve the equation by completing the square: $y^2 - 12y + 54 = 5$ $6 - 13i, 6 + 13i$ $6 - \sqrt{13}i, 6 + \sqrt{13}i$ $-6 + 13i, -6 - 13i$ $-6 - \sqrt{13}i, -6 + \sqrt{13}i$ $-13 - \sqrt{5}i, -13 + \sqrt{5}i$
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Step 1: Move the constant term to the other side of the equation: y^2 - 12y + 54 - 5 = 0 y^2 - 12y + 49 = 0 Show more…
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