00:01
I'm going to solve an equation on the interval 0 to 2 pi.
00:05
I have tan of 3x equal to 1.
00:10
So i want to think in tangent period, which is 0 to pi, where is the tangent 1? and that is going to be tangent is 1 at pi over 4.
00:23
And then i want to put plus k pi.
00:26
Now i'm going to multiply through by 1 .3.
00:28
So x is going to be pi over 12 plus pi over 3 times k.
00:38
Now if k is 0, then i'm just going to get pi over 12.
00:45
If k is 1, i have pi over 12 plus pi over 3, which is pi over 12 plus 4 pi over 12, which is 5 pi over 12.
00:59
If k is 2, then i have plus 2 pi over 3.
01:08
So that's pi plus 8 pi.
01:11
That's 9 pi over 12.
01:18
And i can reduce that to 3 pi over 4.
01:24
If k is 3, i have pi over 12 plus pi.
01:31
So that's going to be pi over 12 plus 12 pi...