Solve the following equations in the interval ( [0,2 pi] ). Note: Give the answer as a multiple of ( pi ). Do not use decimal numbers. The answer should be a fraction or an integer. Note that ( pi ) is already included in the answer so you just have to enter the appropriate multiple. E.g. if the answer is ( pi / 2 ) you should enter ( 1 / 2 ). If there is more than one answer enter them separated by commas. [ egin{array}{l} sin (t)=-frac{sqrt{3}}{2} \ mathrm{t}=square pi \ sin (t)=-frac{sqrt{2}}{2} \ mathrm{t}=square pi end{array} ]
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To find the solutions for \( t \) in the interval \( [0, 2\pi] \), we need to consider the unit circle and where the sine function equals \( -\frac{\sqrt{3}}{2} \). The sine function is negative in the third and fourth quadrants. Show more…
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Solve the following equation in the interval [0, 2 π]. Note: Give the answer as a multiple of π. Do not use decimal numbers. The answer should be a fraction or an integer. Note that π is already included in the answer so you just have to enter the appropriate multiple. E.g. if the answer is π/2 you should enter 1/2. If there is more than one answer enter them separated by commas. (sin(t))^2=3/4
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