solve the following inequality. Write the answer in intervals {[x(x-3)]/[x^2-1x-72]}<=0
Added by Kunal G.
Step 1
The denominator can be factored as x^2 - x - 72 = (x - 9)(x + 8). The numerator can be factored as x(x - 3). So, the inequality becomes: [x(x - 3)]/[(x - 9)(x + 8)] <= 0 Show more…
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