Question

Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.\\ $x^2 - 12x + 36 < 0$\ Use the inequality in the form $f(x) < 0$ to write the open intervals determined by the boundary points as they appear from left to right on a number line. Choose the sign that describes the function values of $f(x)$ for each of these intervals.\ Interval\\Sign\\(Simplify your answers. Type your answers in interval notation. Type exact answers, using radicals as needed. Use integers or fractions for any numbers in the expressions.)

          Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation.\\
$x^2 - 12x + 36 < 0$\
Use the inequality in the form $f(x) < 0$ to write the open intervals determined by the boundary points as they appear from left to right on a number line. Choose the sign that describes the function values of $f(x)$ for each of these intervals.\
Interval\\Sign\\(Simplify your answers. Type your answers in interval notation. Type exact answers, using radicals as needed. Use integers or fractions for any numbers in the expressions.)

$Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation. x^2 - 12x + 36 < 0Use the inequality in the form f(x) < 0 to write the open intervals determined by the boundary points as they appear from left to right on a number line. Choose the sign that describes the function values of f(x) for each of these intervals.Interval Sign (Simplify your answers. Type your answers in interval notation. Type exact answers, using radicals as needed. Use integers or fractions for any numbers in the expressions.)$

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