00:01
In this problem, we have been asked to solve the given equation for x.
00:05
So the equation given is the determinant of x minus 2, 2, 3, x minus 1.
00:13
This is equal to 0.
00:15
So in order to solve this equation, first of all, let us expand this determinant.
00:19
So this will be this number times this number minus this number times this number.
00:25
So that means x minus 2 times x minus 1 minus 2 times 3 which is 6 this is equal to 0.
00:34
So we have x square minus x minus 2x plus 2 minus 6 is equal to 0.
00:43
So we have x square minus x minus 2x that is minus 3x and plus 2 minus 6 that is minus 4.
00:51
So we have a quadratic equation which we need to solve.
00:54
So, in order to solve this quadratic equation, we need to find a pair of numbers whose product will be minus 4 times 1 because the coefficient of x squared is 1.
01:06
So we need two numbers whose product is negative 4 and whose sum is negative 3...