00:01
So for this problem, we're given the square root of x squared plus 3 equals the square to 28.
00:06
And with an algebra, we need to isolate the variable, in this case, x.
00:11
And in order to do that, you have to do the inverse operation.
00:14
So if we're taking the square root, then we need to square it.
00:18
We need to do it on both sides as well in order to maintain the equals sign to keep it balanced.
00:24
So the square roots will cancel because of the squared.
00:27
And this will leave us with x squared plus three equals 28 so in order to get rid of the three because we're trying to get the x by itself we're going to subtract three on both sides so x squared equals 25 and then one more step we need to get rid of this squared right here so in order to do that you're going to use the square root function by using the square root operation you have to do it on both sides.
01:00
This will get rid of the squared, but in the process, it'll actually make this plus minus.
01:04
So x is equal to plus or minus the square root of 25...