00:01
Okay, so we're given this a quality and we're supposed to solve it.
00:04
So we can start off by doing this by writing it in terms of like zero.
00:11
Okay, if we do this, then if we multiply 3x plus 2 on both sides, we get 2 minus 2x is equal to 0.
00:21
This under being 2x is equal to 2, x is equal 1.
00:26
This is a critical point, which image both sides are equal.
00:29
So there's a point between this inequality.
00:32
If we were to write x, we can solve it also.
00:38
What was it supposed to be? x is greater than one, right? you want, actually, you can do this width beside.
00:55
So 2 minus 2x is greater in 0.
00:59
That means 2x is on one side.
01:02
We get 2x, 2 minus 2x.
01:05
2 is less than 2.
01:07
2 is lessen to x that means we can write it like this and yeah divide both sides by 2 we get x x is squared than 1 okay that's one side of our inequality so x is greater in one now that this has inequality we know that there's a critical point in which this denominator would be 0 this denominated is then this inequality becomes imaginary or like undefined.
01:42
So we don't really want that point, but we know that at that point exists.
01:47
So there has to be something that's less than or greater than this point...