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Solve the right triangle. M= ° (Round to one decimal place as needed.) n= ° m (Round to the nearest integer as needed.) p= ° m (Round to the nearest integer as needed.) 

          Solve the right triangle.
M= ° (Round to one decimal place as needed.)
n= ° m (Round to the nearest integer as needed.)
p= ° m (Round to the nearest integer as needed.)
Solve the right triangle. M= ° (Round to one decimal place as needed.) n= ° m (Round to the nearest integer as needed.) p= ° m (Round to the nearest integer as needed.)

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Introductory and Intermediate Algebra for College Students 4th
Introductory and Intermediate Algebra for College Students 4th
Robert Blitzer 4th Edition
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Solve the right triangle. M = 56.3° (Round to one decimal place as needed.) n = 56 (Round to the nearest integer as needed) p = 56 (Round to the nearest integer as needed.) Solve the right triangle M = 56.3° (Round to one decimal place as needed) n = 56 (Round to the nearest integer as needed) p = 56 (Round to the nearest integer as needed)
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Transcript

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00:01 So in this given question, this is given that in this right triangle triangle, this hypotenuse is 15, this base is 12 meter and height x is x.
00:07 Okay, so we have to find a value of x.
00:09 Now by applying pythoros theorem, as this is the right triangle triangle, we will apply pythoros theorem...
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