Solve the system. \[ \begin{aligned} 3 x-y+z & =3 \\ -x+y+2 z & =0 \\ -5 x+3 y+2 z & =-2 \end{aligned} \] \[ \begin{array}{l} x= \\ y= \\ z= \end{array} \]
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\[ \begin{aligned} 3x - y + z &= 3 \quad \text{(Equation 1)} \\ -x + y + 2z &= 0 \quad \text{(Equation 2)} \\ -5x + 3y + 2z &= -2 \quad \text{(Equation 3)} \end{aligned} \] Show more…
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