00:01
To solve this system of linear equation, we write down the augmented matrix.
00:08
So it is 1, negative 1, 4, negative 4, 4, negative 3, 3, negative 8, negative 3, 0, 27, negative 12.
00:29
Then we do row operations.
00:31
We use the first row to eliminate this 4 and this 3.
00:36
So negative 4 times of first row added to second row and then 3 times of the first row added to the third row.
01:11
Next thing, we note that third row is the negative 3 times of the second row.
01:19
So we add 3 times of the second row to the third row.
01:24
Third row becomes all 0.
01:35
Also, we use this negative 1 to eliminate this negative 1...