00:01
This problem gives us a system to solve of equations, and we want to use any method.
00:05
So to make this as fast as possible, since we have two methods we could use for systems, either elimination or substitution, substitution would be the fastest because we already have x isolated.
00:17
And if x is equal to 4y plus 4 in one equation, that means the x and the other equation has to equal the same thing.
00:23
So we can replace 2 times x with 2 times 4y plus 4, still plus 2y, equal to 5 and now we have an equation all in terms of y so we can solve for y and then we can go back to this isolated equation for x and find what x is so to solve for y will distribute two first which will give us 8 y plus 8 plus 2y equal to 5 8 y and 2y give us 10 y still plus 8 equal to 5 when we subtract 8 from both sides that gives us 10 y equal to 5 minus 8 which is negative 3 and then when we divide both sides by 10 that gives us a our y value of negative three tenths.
01:03
And once we have the y value, now we can go back, like we said, and plug into either equation, really.
01:08
But since x is already isolated in the second equation, we'll plug in there...