00:01
Alright, let's solve the following system.
00:03
So we've got negative 1, 1, 1, negative 1, 2, negative 3, negative 3, negative 2, negative 7, 0.
00:14
3, negative 2, negative 7, 0.
00:19
So we can use our first row to get rid of our second and third row.
00:24
So row 2 minus row 1 and row 3 plus 3 row 1.
00:33
So for right now i am not changing my first row.
00:37
Second row, negative 1 minus negative 1 is 0.
00:40
2 minus 1 is 1.
00:42
Negative 3 minus 1 is negative 4.
00:45
Negative 4 minus negative 1 is a negative 3.
00:50
For my third row, 3 plus negative 3 is 0.
00:56
Negative 2 plus 3 is 1.
01:00
Negative 7 plus 3 is negative 7 plus 3 is negative 4.
01:07
And 0 plus negative 3 is negative 3.
01:12
So here we're going to have one row cancel out another row.
01:17
So let's do this.
01:20
Row 3 minus row 2.
01:22
So we're going to end up having a dependent system here...