Q1: (5 points) Observation from two random and independent samples, drawn from population 1 and 2, are given below Sample 1 33 61 20 19 40 Sample 2 26 36 65 25 35 Preliminary calculations show that: $\bar{x}_1 = 34.6$, $s_1 = 17.2$, $\bar{x}_2 = 37.4$, $s_2 = 16.2$. 1. Assume that the two populations are normal with equal variances. Use the pooled t-test for testing $H_0: \mu_1 = \mu_2$ vs. $H_1: \mu_1 \neq \mu_2$, where $\mu_1$ is the mean of population 1 and $\mu_2$ is the mean of population 2. Use $\alpha = 0.1$. (2 points) 2. Use the Wilcoxon rank sum test to determine whether or the two populations are the same or not. Use $\alpha = 0.1$. (3 points)
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To find the mean of population 2, we can use the formula: Mean of population 2 = Mean of Sample 2 + (Mean of Sample 2 - Mean of Sample 1) Mean of population 2 = 17.2 + (17.2 - 34.6) Mean of population 2 = 17.2 + (-17.4) Mean of population 2 = -0.2 Therefore, the Show more…
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