Solving for sample size with given margin of error $frac{alpha}{2} = frac{1 - CL}{2}$ $z_{frac{alpha}{2}} = ext{invNormal} left( 1 - frac{alpha}{2} ight)$ $EBM = z_{frac{alpha}{2}} sqrt{frac{p'q'}{n}}$ A political candidate has asked his/her assistant to conduct a poll to determine the percentage of people in the community that supports him/her. If the candidate wants a 10% margin of error at a 90% confidence level, what size of sample is needed? Be sure to round accordingly. $cdot$ Find $frac{alpha}{2} = $ $cdot$ Find $z_{frac{alpha}{2}} = $ Round to 2 decimal places. $cdot$ Since we are not given any information about the population proportion, we are going to guess the value of $p' = $ $cdot$ Using the EMB formul to solve for $n = left( frac{z_{frac{alpha}{2}}}{EBM} ight)^2 p'q'$. Make sure to round UP to a whole number answer. The candidate would need to survey people in the community in order to be within a 10% margin of error at a 90% confidence level.
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