00:01
Hello everyone.
00:02
In the present problem it is given that rate of decay is 432 per second at t is equal to 15 minutes.
00:13
At t is equal to 48 minutes, counting rate is 230 per second.
00:20
Coming to the solution, we have.
00:29
Suppose initial unstable nuclei is equal to n.
00:44
At t is equal to 15 minutes we have d n divided by d t is equal to plus lambda n here n1 is the number of undecade nucleide at t is equal to 15 minutes.
01:36
Therefore, 432 is equal to plus lambda n1.
01:43
Let this be equation 1.
01:48
At t2 is equal to 48 minutes we have d n divided by d t is equal to is equal to.
02:03
Plus lambda n2.
02:08
N2 is number of undecade nuclei at t is equal to 48 minutes.
02:30
This implies 213 is equal to plus lambda n2.
02:41
Let this be equation 2.
02:53
Dividing equation 1 by equation 2 we have 432 divided by 213 is equal to plus lambda n1 divided by plus lambda n2 is equal to n1 divided by n2.
03:18
Let this be equation 3.
03:21
We know n0 e raised to minus lambda t.
03:36
So 432 divided by 213 is equal to n0 e raised to minus lambda t1 divided by n0 e raised to minus lambda t1 divided by n0 e raised to minus lambda t2.
03:56
This is equal to e raised 2 minus lambda t1 minus of minus lambda t2...