00:01
So for this problem, we're given a 4 meter long pole standing vertically in a lake.
00:18
The depth of the lake is 2 meters.
00:26
The sun is at an angle of 40 degrees above the horizon.
00:35
And the index of refraction for water is n is equal to 1 .33.
00:41
So we need to find the length of the pole's shadow on the lake bottom caused by refraction of sunlight at the water surface.
00:49
So the first thing we need to do is to find the brake the pool into two parts.
00:55
So we have the part in the air.
00:57
We'll call this h .h.
01:01
Air.
01:02
And this is equal to 4 meters minus 2 meters.
01:06
It's equals to 2 meters.
01:07
And then we have the part in the water.
01:09
We'll call this h water.
01:10
And this is just going to be 2 meters.
01:14
Now use snell's law for refraction.
01:17
So you have an air times sign.
01:20
Theta air is going to be equal to n water times sine theta water...