00:01
Okay, so for this question, we have to form some equations in two variable and then we have to solve them by any algebraic method.
00:10
So we can use any method that is substitution method or elimination method for solving these two equations.
00:17
So our first, the first part is a part of monthly hostel charges is fixed and remaining depends on the number of days.
00:28
Okay, so let's say the fixed.
00:30
Charges are x and let's say the mess fees per day, the mess fees per day is y.
00:43
Okay, it says that when a student a takes for the food for 20 days, okay, she have to pay the fixed charges plus the mess charges for 20 days and she pays thousand bucks.
01:04
This is our first equation.
01:06
And in the second equation we are given that she stays for 26 days so the fixed charges would be x and mess fees will be for 26 days and it is given to be 1 180 this is our equation 2 we can see by equation that we can simply solve it by elimination method that is subtracting these two equations so just simply subtracting these two equations so just simply supplication attracting the two equations, we get 6y equals to 180.
01:44
That is y is equals to 30.
01:49
So mess charges are 30 rupees per day.
01:52
Similarly, we can find x which comes out to be 400.
01:57
So fixed charges are 400 rupees.
02:01
Okay.
02:02
Moving on to the second part, moving on to the second part, it's talks about a fraction.
02:18
So let's say the fraction is x upon y.
02:22
The fraction is x upon y.
02:24
The numerator is x and the denominator is y.
02:27
So the condition we are given is when we subtract one from the numerator the fraction becomes 1 by 3.
02:36
Okay.
02:37
Solving this we get 3 into x minus 1 is equals to y that is 3x minus y is equals to 3 this is our equation one for case 2 we are given that when we add 8 to the denominator the fraction becomes 1 by 4 that is 3x minus y sorry 4x 4x minus y equals to 8 okay so we can simply see that subtracting those these two equation we can eliminate y so we we will just subtract those these two equations 3x minus y equals to 3 and 4x minus y equals to 8 subtracting those these two equations we get the value of x to be 5 and the value of y to be 12 so the fraction would be 5 upon 12 okay so moving on to the third part it talks about some questions the total number of questions okay so the total number of questions will be would be incorrect questions plus the correct questions okay so let's say the correct questions are x and the incorrect questions are why okay we will make the equations on the basis of the given marks okay so it says for the right answer he gets three marks okay so three marks for the right answer and minus one for the wrong answer and he gets 40 score okay so so this is our equation first.
04:53
For second equation, we are given that if four marks would have been given for the correct answer and two marks would have been deducted for the incorrect ones, that he would have got 50 marks.
05:06
Okay...