00:01
Over here, dimension system of type h is equal to p squared divided by xm minus v.
00:10
Now with v is equal to vx, therefore d divided by d t in p would be equal to 1 divided ih t h t h minus hp.
00:26
So from here what we get is 1 divided by ih where we have this.
00:34
And the another one would be minus v -x.
00:41
So, both are the part of this.
00:43
Well, vx, comma, p is equal to ih, v -x.
00:47
Now, smaller arguments applies that d divided by d t, x would be equal to 1 divided by m.
00:55
P.
00:56
For free particles, h would be equal to, for free particles, h would be equal to p squared divided by 2m.
01:07
And v would be equal to 0.
01:10
So this implies that d divided by d t, p is equal to 0, which means that this is constant...