00:01
So here in this problem we have been given that to come out of the barrel completely, the bullet takes 2 .5 times 10 raise to minus 3 seconds, and the mass of the bullet which is given is 15 grams.
00:20
So that's 15 times 10 raise to minus 3 kg.
00:24
So here we have been given that the bullet, once it is fired from the gun, it comes out of the barrel with a speed of 715 meter per second.
00:40
And we assume the speed to be increasing at a uniform rate.
00:47
We need to figure out the force that is exerted on this bullet.
00:53
So to figure out the force, we know that the bullet starts from rest and it's able to attain the speed in 2 .5 milliseconds.
01:04
So first we will figure out the acceleration that will be v minus u by t.
01:09
So v is the final velocity with 715.
01:13
Initially it's zero and divide it by the time that's 2 .5 into 10 raise 2 minus 3.
01:19
So the acceleration here comes out to be 2 .86 into 10 raise 2...