00:01
Hi, i'm david and i'm here to help you answer your question.
00:03
In the question here, we are going to discuss about the sampling distribution of the sample mean.
00:08
We remind you that for the central limit theorem, if we have the x that follows by the normal, then the symbol mean xx also followed by the normal, where we have the mean of the xxby equal to the mean in the population, standard division xxby equal to the sigma divan by squatter the n.
00:28
Now i see you answer most of the questions correctly, so good job on your work.
00:33
And i just borrowed the result from the part a from you.
00:38
We have the x bar we follow by the normal, while we have the mean of the x bar equal to the two and the standard division x bar equal to 0 .0.
00:50
125.
00:51
And i see only the question d you got, you didn't got it, so i will do the question d for you.
00:57
Now for the d, suppose that the machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 2 .0 5 millimeters.
01:09
Once you find the probability that the problem could be detected when the next symbol is taken.
01:16
And then the hint here, this will occur if the x bar will be greater than the 2 plus 3 sigma bar or the x bar will be smaller than the 2x bar.
01:27
2 minus 3 standard division when the mean equal to the 2 .05.
01:34
So it means don't want to find the probability that the x bar it will be greater than the 2 plus with the 3 standard division will be the 0 .0125.
01:51
R will be the plus...