Starting with an initial speed of 500 ms at a height of 0300...

Starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50-kg ball swings downward and strikes a 4.60-kg ball that is at rest, as the drawing shows. (a) Using the principle of conservation of mechanical energy, find the speed of the 1.50-kg ball just before impact. (b) Assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision. (c) How high does each ball swing after the collision, ignoring air resistance?

Transcript

00:01 Hello, it is given in the question that the mass of ball 1.

00:03 So this is the parameters of ball 1.

00:05 So let us consider this is a ball 1 and in the ball 1 we have mass of the ball 1 that is equal to 1 .5 kgs it is given already and the velocity, initial velocity of the ball that would be equal to 5 meter per second and we have to consider the height h of the ball that is equal to 0 .3 meters.

00:24 So now let us consider bit a of the question.

00:27 So we have to consider the velocity of ball 1.

00:29 Just before the collision let us consider that velocity is v2 so v2 is the velocity of ball 1 that is ball 1 just before collision this is just before collision so we have to find this so let us now apply law of conservation of energy to this so it is good half m v1 whole square plus m g h that would be equal to half m v2 o square from here we can find the value of v2 the v2 would be equal to v1 whole square plus 2 gh square root of it.

01:01 So from here we can put the values of quantity into the expression.

01:04 We get 25 plus 2 multiplied 9 .8.

01:07 This is 8 over here.

01:08 So 8 multiplied 0 .3, this is 0 .3 and square root of it.

01:14 So we get that it is the value of v2, that is the velocity of ball 1 just before collision is about 5 .56 meter per second.

01:23 So this is the answer to the first bit of the question, a bit of the question.

01:27 The velocity of ball 1 just before collision.

01:29 Let's consider pbitt of the question.

01:31 So it is given that ball 2, the parameters of ball 2, that is the mass of ball 2, m equal to 4 .6 kages.

01:38 This is big m over here.

01:40 Now let us consider velocity v.

01:42 This velocity v is the velocity of ball 2 just after collision.

01:49 That is just after collision.

01:54 Now let us consider the same for ball 1.

01:57 This is the velocity of ball 1.

02:03 Just after collision.

02:06 So this is just after the collision.

02:09 Now let us consider that the collision is elastic in nature.

02:12 It is given that collision is elastic and from there we have to consider we have to find the value of v3 and v that is the velocity of ball 1 in 2 just after collision...

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