00:01
Hey there, welcome to numerate.
00:04
So we are given a standard normal curve here, where we have our critical value labeled on the right -hand side.
00:12
So what we basically are given is a t -critical value that equals 1 .834.
00:28
All right, 1 .834.
00:31
And we want to see whether the standardized test statistic, t, in a case, that you should reject the null hypothesis.
00:41
So basically what we're given here is parts a to d with our t score equation.
00:49
And we are trying to reject or fail to reject the null hypothesis.
00:54
So let's start by writing our decision rule here.
01:01
So basically what we have is our t score.
01:05
Now when our t score is greater than our t critical value, then this will be rejecting the null hypothesis.
01:26
Vice versa, if our t score here is less than rt critical value of 1 .8 -34, then we are going to fail to reject the null hypothesis.
01:47
All right, awesome.
01:50
So let's carry on by starting with part a.
01:55
So for part a, we're given a t score of 1 .8.
02:01
So, with 1 .863, we can see that 1 .863 is greater than 1 .834.
02:15
So therefore, we are going to reject the noaa hypotheses because our t score here is greater than 1 .834...