00:01
In this given question, we are assigned with the task to calculate the number of electrons and protons present in each of the given ion.
00:11
The ion given in part a is chromium 3 plus ion.
00:18
Now let us look at the atomic number and electronic configuration of chromium 3 plus ion.
00:23
Or else, atomic number is more than enough to give the count of electrons and protons present in each ion.
00:30
Atomic number of chromium is 24.
00:32
Since the oxidation number of chromium is 3 plus, it has lost 3 electrons.
00:38
Therefore, the number of electrons present in chromium 3 plus is 21.
00:45
Therefore, number of electrons in chromium 3 plus is 21, whereas number of protons in chromium is 24.
00:52
The ion given in part b is selenium 2 minus ion.
00:58
Atomic number of selenium is 34...