A stationary 4-kg shell explodes into three pieces. Two of...

A stationary 4-kg shell explodes into three pieces. Two of the fragments have a mass of 1 kg each and move along the paths shown with a speed of 10 m/s. The third fragment moves upward as shown. 2 kg 1 kg 60° 60° 1 kg 10 m/s 10 m/s What is the initial total momentum of the system? kg m/s What is the final total momentum of the system? kg m/s What is the speed of the third fragment? m/s Is kinetic energy conserved?

Transcript

00:01 In this question, we are given here stationary 4 kilogram cell exploit.

00:05 So here we are given here, stationary that 4 kilogram which is equal to 4 kilogram the cell explode into 3 pieces.

00:17 Now the 2 of the fragment have a mass.

00:21 So here we can write, m1 which is equal to 1 kilogram mass, then move along the path.

00:26 So the speed, v1 which is equal to 10 meter per second.

00:30 The third fragment here this is our second fragment we are given here this is our 2 kilogram 4 kilogram is our here 4 kilogram is our total mass now it is it is explode so it is 1 kilogram is in the one direction and it makes angle teta which is equal to 60 degree now another fragment is goes m2 which is equal to 2 kilogram and here we can write that it moves towards the it's move with velocity 10 meter per second and theta to which is equal to it makes 60 degree and third fragment that moves towards the opposite direction of this two and here we can wait it mass here a mass 1 kilogram and 3rd fragment have a mass here 2 kilogram and here we know that the 4 kilograms cell into 3 pieces the 2 fragment have a mass 1 kilogram and the our third fragment here we have a 3rd fragment have a mass of here we are given here of 2 kilograms that moves towards the opposite direction now here it we can we want to find the initial momentum initial momentum of the system so first we can write here we can write the velocity of v2 here we can write velocity of v2 which is equal to 10 meter per second and multiple we can write minus 60 degree here we can write minus 60 degree i karet minus we can write pause 60 degree j karat and here after simplification we can write here answer is so v2 which is equal to answer it is minus 8 .67 i karet minus we can write 5 j kare meter per second now mass of the third fragment here same of the mass v1 so here velocity v1 let's talk about velocity v1 so velocity v1 which is equal to we can write same it is 8 .67 i .kare minus 5g .kare is in the meter per second...

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